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JEE Main 2017 Counselling

JEE Main 2017 (Joint Entrance Examination) is organized by CBSE for engineering aspirants who wish to pursue various UG programs offered by different engineering colleges across India. The JEE Mains Results is expected to be declared by April 27, 2017 and successful candidates are allowed to participate in JEE Main Counselling as per their order of merit. The candidates are offered admission in their choice of course and college, subject to availability and on the basis of All India Rank of a candidate. 

The JEE Main 2017 Counselling Process is tentatively scheduled to start from June 24, 2017. The admissions to the seats offered by Participating Institutes through JEE Main 2017 and JEE Advanced 2017 take place through three counselling process mentioned below and the JEE Main Seat Allotment Process.

  1. JOSAA Counselling Process: JoSAA is now the only authority that grants admissions in IITs, ISM Dhanbad, NITs, IIITs and GFTIs (Government Funded Technical Institutes) through JOSAA Counselling Process. 
  2. CSAB NEUT Counselling: This counselling process is conducted by the CSAB Board for admissions to the institutes of the North Eastern States and the Union Territories.
  3. CSAB SFTI Counselling: The admissions to self-financed technical institutes via JEE Main 2017 is conducted by this counselling process.

JEE Main 2017 Counselling Dates

The tentative JEE Main 2017 Counselling schedule is being mentioned below. Candidates can check detailed schedule to plan their participation accordingly:

Online Registration and Choice FillingJune 24, 2017 - June 29, 2017
Display of mock seat allocationJune 27, 2017
Seat Allotment (First round)June 30, 2017
Physical Reporting (First round)July 1, 2017 - July 5, 2017
Display of filled / available seatsJuly 6, 2017 (10:00 am)
Seat Allotment (Second round)July 6, 2017 (05:00 pm)
Physical Reporting (Second round)July 7, 2017 – July 9, 2017

JEE Main 2017 Selection Criteria

For selection through JEE Main 2017, CBSE would incorporate a two stage process. In this process, your performance in the Class 12 or equivalent qualifying examination and in JEE Main examination is considered with 60% weightage is given to the candidate's JEE Main performance and 40% weightage is given to Class 12th or equivalent qualifying examination performance

So lets discuss one by one, the  role of qualifying marks in the selection-

Role of qualifying marks in selection

Qualifying marks have been divided in three categories:

  • Class XIIth marks-Normalization or standardization process is used by CBSE for calculation of Class 12 marks. According to JEE Interface Group guidelines, 50% board marks will be normalized by equating percentile of different boards.
  • Calculation of Percentile of XIIth marks in JEE Main:To calculate percentile first thing you need to understand the basic difference between the two - percentage & percentile. Percentage is the number calculated out of 100. Percentile reflects how many students have scored below that student whose percentile is required to be calculated. It presents you the clear picture of your performance in a competitive exam. For example – If your score in JEE MAIN is not so good then after percentile calculation you came to know, how much extra efforts you need to add for required score.Go through the simple formula to understand the concept of percentile:

Add Z number of students in the group with total marks less than the student whose percentile is required to be estimated.

Number of students who have registered for exam: 14198

Number of students who have appeared for exam: 13711

Case 1: A candidate has scored 45% marks in board & 2328 students have scored below him – Percentile score for 45% marks in board: 2328*100/13711=16.09

Case 2: A candidate has scored 50% marks in board & 6885 students have scored below him – Percentile score for 50% marks in board: 6885*100/13711=50.21. 

Important points to note-

  • Normalization marks of a student depends on his/her position in board list.
  • Students who are going to appear for Improvement exam in Class XIIth have to appear in all five subjects.
  • Marks obtained in two different years in case of improvement will not be considered in normalization system.

JEE Main score- The JEE Main score will be determined on the basis of your performance in Paper-1 & Paper-2 and 60% weightage will be given to your performance while preparing the rank list. So, it is very important to perform well in it. Moreover,  your  JEE Advanced Exam eligibility will be determined on the basis of the JEE Main 2017 Score.


Manipal University B.Tech Admission 2017: Apply Online Here
VIT University B.Tech Admission 2017: Apply Online Here
Jain University B.Tech Admission 2017: Apply Online Here
Chandigarh University B.Tech Admission 2017: Apply Online Here

Selection criteria for NITs

Board Marks40
Performance in JEE Main60

Performance with respect to above parameters  gives you the chance for choice locking for NIT’s & for other universities too. Admission in NIT’s is solely the decision of NIT authorities only. If there is any student who have cleared JEE Advanced then preference will be given to him/her over the one who have applied through JEE main score only.There are almost 25000-30000 seats available in IIT’s, NIT’s & IIIT’s in total.  Up to rank of 70000 you can expect last NIT & in extreme cases up to 80000.

JEE MAIN 2017JEE Mains ResultJEE Main SyllabusJEE Main Cut off

JEE Main 2017 Selection Procedure of Colleges other than IIT’s

Colleges other than IIT’s have some different selection process which we have mentioned here:

  1. Distribution or Diversification of marks obtained in JEE Main in Mathematics, Physics & Chemistry. Students who have scored better get a chance on priority basis in terms of their rank.
  2.  Diversification on the basis of positive & negative marks:

You can understand this with an example. Let us say a student has scored total 232 & other one scored 212 marks out of 360, & subject wise weightage is given below:

SubjectStudents (1) weightage of marksStudent (2) weightage of marksQuestions attemptedNegative marking
Physics7082Total attempt- 673
   Wrong attempt- 3 
Chemistry7076Total attempt-79 Wrong attempt-2626

Student 2 would have been ranked higher than student 1 in the merit list & will be called first for choice locking. Student with higher absolute value will be ranked on top in the merit list.

Note: Absolute value is the ratio of positive & negative marks obtained by a student. After adopting this process if there is no any chance of further resolution then students will be allotted same rank.

  • Now your question is quite obvious that how negative marking affects your admission through counselling?

Student 1 has solved only 64 questions in total, & most of them are correct. In case of student 2 who has solved 79 questions, attempts 26 incorrect questions. Conclusion is that if 2 has not solved too many questions then he has more chances of getting good score & rank in merit list too. So try to avoid temptation of solving questions with probable answer.JEE Main 2017 Admission Process in B.Arch/B.Planning courses in colleges other than IIT’s:

  • Distribution or Diversification of marks obtained in Aptitude & Drawing test of Paper 2 of JEE Main. Students who have scored better get a chance on priority basis in terms of their rank.
  • Resolution will be carried out on the basis of Normalization of marks in qualifying marks. Higher normalized marks better position in merit list.
  • Resolution of Positive marks will be carried out as same as given in JEE Main Exam Pattern

Chances of Selection:-Possibilities of selection will entirely depend on certain factors given below:

  1. Performance in JEE (Main)
  2. JEE (Main) Cutoff
  3. Call for short listed students
  4. Choice Locking through Counselling

Note: If a student who has received call regarding short listing, but have not attended the count selling proceedings then in place of that other student with lower rank will get call for choice licking. We strongly advise you to not to miss the counselling.

JEE Main 2017 Normalization of Marks

The process used for admission in various NIT’s, IIIT’s & CFTI’s has been adopted in JEE Main 2017. This process has been carried out on class 12TH marks only.

Why Normalization?

This is the way of indexing a large amount of ambiguous data in an unambiguous way. It does not include any type of redundancy in the date but presents a clear picture of figures.

To identify which subjects have been considered for all calculations, you can go through the eligibility criteria of JEE Main. In case of alternative subject best marks will be considered.

  • Calculation of XIIth marks through normalization:
  1. Let us say, A0 is the total marks obtained by students in JEE (Main)
  2. B0is the total marks obtained by students in five subjects in their respective board & their percentile have been termed as P. This score has been computed by considering all students of that board.
  3. Estimate JEE (Main) marks with respect to percentile on all India basis & named it as B1.
  4. Now, calculate JEE (Main) marks corresponding to percentile (P) with respect to set of marks obtained in JEE (Main) by the student of that board. Embrace this as B2.

Normalized Score would be compiled as (Bnor): 0.5* (b1+b2)

Admission into CFTI’s:

Normalization formula is slightly different for (CFTI’s). Here performance in JEE (Main) & Normalized board performance matters the most. It has been considered in the ratio of 60: 40.

Apply this formula, C= 0.6*A0+ 0.4* B nor.

Note: Parameter B 0 has been decided only to perform basic calculations for normalization.

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