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**GATE 2017** exam will be conducted in the month of February and the result is expected to come out in the month of March. As per the **GATE Official brochure**, the result is expected to be out on March 27. 2017. The results generally concerned with the marks obtained by a candidate along with the All India Rank (AIR) as obtained. However, GATE score is also displayed along with the cut off for the various categories.

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Post the conduct of the examination, the marks as obtained by the candidate in the examination are calculated. This score is a direct calculation of summation of marks for the correct answers and deduction of negative marks for wrong answers. This score is a raw score for all the candidates. This raw score is then converted into a **GATE** score with the help of normalization process.

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Scores are normalized to take into consideration various variations in the multiple papers as conducted. These variations could be related to various factors and especially the difficulty level of the examination.

This normalization is based on the assumption that in a multi-session **GATE Examination**, the abilities of the candidates are equally distributed across all the sessions.

This is an important assumption as the number of candidates that appear for multi-examination is generally large and the candidates are randomly allocated these sessions. **GATE Exam** authorities also make sure that the number of candidates in each session are of same order of magnitude.** **

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The papers for which this normalization is used are CE, CS, EC, EE and ME Papers. These are the exams that are conducted in a multiple session.

Normalized mark (︿*M** _{ij}*) of

︿

where,

*M** _{ij}* is the actual marks obtained by the

*M*^{g}* _{t}* is the average marks of the top 0.1 % candidates in all sessions of that subject,

*M*^{g}* _{q}* is the sum of mean and standard deviation of marks of all candidates in all sessions of that subject,

*M** _{ti}* is the average of marks of top 0.1 % candidates in the

*M** _{iq}* is the sum of mean and standard deviation of marks of all candidates in the

Further, the graph can help understand the relationship between the two scores better.

**Graph showing the linear relationship between "actual marks" and "normalized marks" of a candidate, in a multiple-session subject (CE, EE, ME, EE or CE) of GATE.***M*^{g}* _{t}* = average marks of top 0.1 % candidates in all sessions of that subject.

Using the above formulae, the raw score of the multiple session examinations is conducted into a normalized GATE Score.

Normalization Formula for single session examination (h4)

For the single session examination the normalization formula is as given below.

*S = S _{q} + (S_{t}- S_{q}) (M-M_{q})/(M_{t}-M_{q})*

{\displaystyle S=S_{q}+(S_{t}-S_{q}){\frac {M-M_{q}}{{\overline {M}}_{t}-M_{q}}}}

where,

*S* = Score (normalized) of a candidate,

*M* = Marks obtained by a candidate ("normalized marks" in case of multiple-session subjects CE, CS, EC, EE and ME),

*M** _{q}* = Qualifying marks for general category candidates in that subject (usually 25 or μ + σ, whichever is higher),

μ = Average (i.e. arithmetic mean) of marks of all candidates in that subject,

σ = Standard deviation of marks of all candidates in that subject,

*M** _{t}* = Average marks of top 0.1 % candidates (for subjects with 10000 or more appeared candidates) or top 10 candidates (for subjects with less than 10000 appeared candidates),

*S** _{t}* = 900 = Score assigned to

*S** _{q}* = 350 = Score assigned to

By percentile it means, the percentage of candidates that have scored below a particular candidate.

For final GATE Score calculation, the percentile formula is-

*Percentile* = ( 1 - *All India rank*/*No. of candidates in that subject* ) x 100%

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For the calculation of marks in **GATE 2017**, the following things are to be considered-

*M*is usually 25 marks (out of 100) or +_{t}*σ*, whichever is larger.

Here, μ is the mean and σ is the standard deviation of marks of all the candidates who appeared.

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